- Given a binary tree, We would like to find out, whether leaf nodes of a binary are at same level.
- We will use level order traversal or breadth first search (BFS) algorithm to traverse the binary tree.
- What is level in a binary tree?
- Level is distance or hops of node with respect to root node.
- The root node is considered to be at level 0 and immediate children of root node will be at level 1 (level of root node + 1).
- We can calculate the level of all the nodes in binary tree (Refer Fig 1).
Example 1: Given a binary tree (Fig 2), Check whether leaf nodes are at same level.
- Traverse the binary tree using breadth first search algorithm.
- Find out the level of each leaf node. (refer below table).
| S. No. | Leaf Node | Level |
|---|---|---|
| 1 | D | 2 |
| 2 | E | 2 |
| 3 | F | 2 |
| 4 | G | 2 |
- Create variable level=0, signify the level of binary tree
- Root is at level 0, push the root to queue.
- Add null to the queue (delimiter to know that we have finished the current level)
- Iterate through the Queue
- Pop node from queue
- Check node is null [The delimiter added earlier]
- We are at next level and increment the level
- Verify that popped up node is leaf node (or not)
- First time, we are visiting the leaf node
- Note down the level of leaf node and mark it visited.
- We got the leaf node again
- Compare the already stored level with current level
- If difference return false
- Compare the already stored level with current level
- Else perform rest operations
- First time, we are visiting the leaf node
- Add next level children (left & right child)
- Once we exit the loop, we will know, whether leaves are same level (or not)
Example 2: Check level of leaf nodes in a given binary tree (Fig 3)
We will follow the similar algorithm for current example and we will find out level of each leaf node.
Time complexity: O(n).
Let us look into the complete code as follows:
1.) IsLeafAtSameLevel Class: IsLeafAtSameLevel class is used to check whether leaf nodes of binary tree are at same level using breadth first search recursive algorithm.
package org.learn.Question;
import java.util.LinkedList;
import java.util.Queue;
public class IsLeavesAtSameLevel {
public static boolean isLeavesAtSameLevel(Node root) {
if (root == null) {
System.out.println("Tree is empty");
return false;
}
Queue<Node> queue = new LinkedList<Node>();
queue.offer(root);
// level delimiter
queue.offer(null);
int level = 0;
boolean bLeafFound = false;
int leafLevel = -1;
while (!queue.isEmpty()) {
Node node = queue.poll();
// Level change
if (null == node) {
if (!queue.isEmpty()) {
// level delimiter
queue.offer(null);
}
level++;
} else {
if (node.left == null && node.right == null) {
// first leaf found
if (bLeafFound == false) {
bLeafFound = true;
leafLevel = level;
} else { // Leaves are at different level
if (leafLevel != level) {
return false;
}
}
}
if (node.left != null) {
queue.offer(node.left);
}
if (node.right != null) {
queue.offer(node.right);
}
}
}
return true;
}
}
2.) Node Class: Node class representing the nodes of a binary tree. Node class has following attributes
- Data Node
- left child
- right child
package org.learn.Question;
public class Node {
public int data;
public Node left;
public Node right;
public Node(int num) {
this.data = num;
this.left = null;
this.right = null;
}
public Node() {
this.left = null;
this.right = null;
}
public static Node createNode(int number) {
return new Node(number);
}
}
3.) App Class : We are creating the binary tree in main function & we are calling IsLeafAtSameLevel class, to find out whether leaf nodes are at same level using level order traversal.
package org.learn.Client;
import org.learn.Question.IsLeavesAtSameLevel;
import org.learn.Question.Node;
public class App
{
public static void main( String[] args )
{
//root level 0
Node A = Node.createNode(50);
//Level 1
Node B = Node.createNode(25);
Node C = Node.createNode(75);
//Level 2
Node D = Node.createNode(10);
Node E = Node.createNode(30);
Node F = Node.createNode(60);
Node G = Node.createNode(80);
//Level 3
Node H = Node.createNode(55);
Node I = Node.createNode(65);
//connect Level 0 and 1
A.left = B;
A.right = C;
//connect level 1 and level 2
B.left = D;
B.right = E;
C.left = F;
C.right = G;
boolean isLeafAtSameLevel = IsLeavesAtSameLevel.isLeavesAtSameLevel(A);
if(isLeafAtSameLevel) {
System.out.println("1. Leaf nodes of binary tree are at same level");
} else {
System.out.println("1. Leaf nodes of binary tree are not at same level");
}
//Connect level 2 and level 3
F.left = H;
F.right = I;
isLeafAtSameLevel = IsLeavesAtSameLevel.isLeavesAtSameLevel(A);
if(isLeafAtSameLevel) {
System.out.println("2. Leaf nodes of binary tree are at same level");
} else {
System.out.println("2. Leaf nodes of binary tree are not at same level");
}
}
}
The output of main function [Fig 2 and Fig 3] is as follows:
1. Leaf nodes of binary tree are at same level 2. Leaf nodes of binary tree are not at same level
Download Code – Level of leaf node in binary tree (BFS)